$=\sqrt{6+2\sqrt{2}.\sqrt{3-\sqrt{(\sqrt{3}+1)^{2}}}}$
$=\sqrt{6+2\sqrt{2}.\sqrt{2-\sqrt{3}}}$
$=\sqrt{6+2\sqrt{4-2\sqrt{3}}}=\sqrt{6+2\sqrt{(\sqrt{3}-1)^{2}}}$
$=\sqrt{4+2\sqrt{3}} =\sqrt{(\sqrt{3}+1)^{2}} =\sqrt{3}+1$
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11-09-15 10:55 PM
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