tich phan
$\int\limits_{
2}^{+\infty }(\frac{1}{x^2-1}+\frac{2}{(x+1)^2})dx$
Tích phân
tich phan
$\int\limits_{
0}^{+\infty }(\frac{1}{x^2-1}+\frac{2}{(x+1)^2})dx$
Tích phân
tich phan
$\int\limits_{
2}^{+\infty }(\frac{1}{x^2-1}+\frac{2}{(x+1)^2})dx$
Tích phân