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	11	sửa đáp án		Sửa 01-01-14 01:47 PM m_internet001 154 5
$\int\limits\frac{dx}{\sqrt{(x-\frac{5}{2})^2-(\frac{1}{2})^2}}=-\int\limits\frac{dx}{\sqrt{(\frac{1}{2})^2-(x-\frac{5}{2})^2}}$Đặt $x-\frac{5}{2}=\frac{1}{2}sint\Rightarrow t=arcsin(2x-5)$$\Rightarrow \left\{ \begin{array}{l} dx=\frac{1}{2}cost.dt\\ \sqrt{(\frac{1}{2})^2-(x-\frac{5}{2})^2}=\frac{1}{2} cost\end{array} \right.$$\Rightarrow -\int\limits dt=-t+C=-arcsin(2x-5)+C$ $\int\limits\frac{dx}{\sqrt{(x-\frac{5}{2})^2-(\frac{1}{2})^2}}=-\int\limits\frac{dx}{\sqrt{(\frac{1}{2})^2-(x-\frac{5}{2})^2}}$Đặt $x-\frac{5}{2}=\frac{1}{2}sint\Rightarrow t=arcsin(2x-5)$$\Rightarrow \left\{ \begin{array}{l} dx=\frac{1}{2}cost.dt\\ \sqrt{(\frac{1}{2})^2-(x-\frac{5}{2})^2}=\frac{1}{2} cost\end{array} \right.$$\Rightarrow -\int\limits du=-t+C=-arcsin(2x-5)+C$ $\int\limits\frac{dx}{\sqrt{(x-\frac{5}{2})^2-(\frac{1}{2})^2}}=-\int\limits\frac{dx}{\sqrt{(\frac{1}{2})^2-(x-\frac{5}{2})^2}}$Đặt $x-\frac{5}{2}=\frac{1}{2}sint\Rightarrow t=arcsin(2x-5)$$\Rightarrow \left\{ \begin{array}{l} dx=\frac{1}{2}cost.dt\\ \sqrt{(\frac{1}{2})^2-(x-\frac{5}{2})^2}=\frac{1}{2} cost\end{array} \right.$$\Rightarrow -\int\limits dt=-t+C=-arcsin(2x-5)+C$

	10	thêm 367 ký tự trong đáp án		Sửa 01-01-14 01:43 PM m_internet001 154 5
$\int\limits\frac{dx}{\sqrt{(x-\frac{5}{2})^2-(\frac{1}{2})^2}}=-\int\limits\frac{dx}{\sqrt{(\frac{1}{2})^2-(x-\frac{5}{2})^2}}$Đặt $x-\frac{5}{2}=\frac{1}{2}sint\Rightarrow t=arcsin(2x-5)$$\Rightarrow \left\{ \begin{array}{l} dx=\frac{1}{2}cost.dt\\ \sqrt{(\frac{1}{2})^2-(x-\frac{5}{2})^2}=\frac{1}{2} cost\end{array} \right.$$\Rightarrow -\int\limits du=-t+C=-arcsin(2x-5)+C$ Đợi xíu nhá $\int\limits\frac{dx}{\sqrt{(x-\frac{5}{2})^2-(\frac{1}{2})^2}}=-\int\limits\frac{dx}{\sqrt{(\frac{1}{2})^2-(x-\frac{5}{2})^2}}$Đặt $x-\frac{5}{2}=\frac{1}{2}sint\Rightarrow t=arcsin(2x-5)$$\Rightarrow \left\{ \begin{array}{l} dx=\frac{1}{2}cost.dt\\ \sqrt{(\frac{1}{2})^2-(x-\frac{5}{2})^2}=\frac{1}{2} cost\end{array} \right.$$\Rightarrow -\int\limits du=-t+C=-arcsin(2x-5)+C$

	9	bớt 90 ký tự trong đáp án		Sửa 01-01-14 01:28 PM m_internet001 154 5
Đợi xíu nhá $\int\limits\frac{dx}{\sqrt{(x-\frac{5}{2})^2-(\frac{1}{2})^2}}=ln\left| {\frac{x-3}{x-2}} \right|+C$ Đợi xíu nhá

	8	bớt 99 ký tự trong đáp án		Sửa 01-01-14 01:25 PM m_internet001 154 5
$\int\limits\frac{dx}{\sqrt{(x-\frac{5}{2})^2-(\frac{1}{2})^2}}=ln\left| {\frac{x-3}{x-2}} \right|+C$ $\int\limits\frac{dx}{\sqrt{(x-2).(x-3)}}=\int\limits\frac{(x-2)-(x-3)}{\sqrt{(x-2).(x-3)}}dx$$=\int\limits\sqrt{x-3}dx-\int\limits\sqrt{x-2}dx$$=\frac{2}{3}\sqrt{(x-3)^3}-\frac{2}{3}\sqrt{(x-2)^3}+C$ $\int\limits\frac{dx}{\sqrt{(x-\frac{5}{2})^2-(\frac{1}{2})^2}}=ln\left| {\frac{x-3}{x-2}} \right|+C$

	7	thêm 2 ký tự trong đáp án		Sửa 01-01-14 10:31 AM m_internet001 154 5
$\int\limits\frac{dx}{\sqrt{(x-2).(x-3)}}=\int\limits\frac{(x-2)-(x-3)}{\sqrt{(x-2).(x-3)}}dx$$=\int\limits\sqrt{x-3}dx-\int\limits\sqrt{x-2}dx$$=\frac{2}{3}\sqrt{(x-3)^3}-\frac{2}{3}\sqrt{(x-2)^3}+C$ $\int\limits\frac{dx}{\sqrt{(x-2).(x-3)}}=\int\limits\frac{(x-2)-(x-3)}{\sqrt{(x-2).(x-3)}}dx$$=\int\limits\sqrt{x-3}dx-\int\limits\sqrt{x-2}dx$$=\frac{2}{3}\sqrt{(x-3)^3}-\frac{2}{3}\sqrt{(x-2)^3}$ $\int\limits\frac{dx}{\sqrt{(x-2).(x-3)}}=\int\limits\frac{(x-2)-(x-3)}{\sqrt{(x-2).(x-3)}}dx$$=\int\limits\sqrt{x-3}dx-\int\limits\sqrt{x-2}dx$$=\frac{2}{3}\sqrt{(x-3)^3}-\frac{2}{3}\sqrt{(x-2)^3}+C$

	6	bớt 2 ký tự trong đáp án		Sửa 01-01-14 10:30 AM m_internet001 154 5
$\int\limits\frac{dx}{\sqrt{(x-2).(x-3)}}=\int\limits\frac{(x-2)-(x-3)}{\sqrt{(x-2).(x-3)}}dx$$=\int\limits\sqrt{x-3}dx-\int\limits\sqrt{x-2}dx$$=\frac{2}{3}\sqrt{(x-3)^3}-\frac{2}{3}\sqrt{(x-2)^3}$ $\int\limits\frac{dx}{\sqrt{(x-2).(x-3)}}=\int\limits\frac{(x-2)-(x-3)}{\sqrt{(x-2).(x-3)}}dx$$=\int\limits\sqrt{x-3}dx-\int\limits\sqrt{x-2}dx$$=\frac{2}{3}(\sqrt{(x-3)^3}-\frac{2}{3}(\sqrt{(x-2)^3}$ $\int\limits\frac{dx}{\sqrt{(x-2).(x-3)}}=\int\limits\frac{(x-2)-(x-3)}{\sqrt{(x-2).(x-3)}}dx$$=\int\limits\sqrt{x-3}dx-\int\limits\sqrt{x-2}dx$$=\frac{2}{3}\sqrt{(x-3)^3}-\frac{2}{3}\sqrt{(x-2)^3}$

	5	thêm 10 ký tự trong đáp án		Sửa 01-01-14 10:30 AM m_internet001 154 5
$\int\limits\frac{dx}{\sqrt{(x-2).(x-3)}}=\int\limits\frac{(x-2)-(x-3)}{\sqrt{(x-2).(x-3)}}dx$$=\int\limits\sqrt{x-3}dx-\int\limits\sqrt{x-2}dx$$=\frac{2}{3}(\sqrt{(x-3)^3}-\frac{2}{3}(\sqrt{(x-2)^3}$ $\int\limits\frac{dx}{\sqrt{(x-2).(x-3)}}=\int\limits\frac{(x-2)-(x-3)}{\sqrt{(x-2).(x-3)}}dx$$=\int\limits\frac{dx}{\sqrt{x-3}}-\int\limits\frac{dx}{\sqrt{x-2}}$$=2\sqrt{x-3}-2\sqrt{x-2}+C$ $\int\limits\frac{dx}{\sqrt{(x-2).(x-3)}}=\int\limits\frac{(x-2)-(x-3)}{\sqrt{(x-2).(x-3)}}dx$$=\int\limits\sqrt{x-3}dx-\int\limits\sqrt{x-2}dx$$=\frac{2}{3}(\sqrt{(x-3)^3}-\frac{2}{3}(\sqrt{(x-2)^3}$

	4	bớt 1 ký tự trong đáp án		Sửa 01-01-14 10:18 AM m_internet001 154 5
$\int\limits\frac{dx}{\sqrt{(x-2).(x-3)}}=\int\limits\frac{(x-2)-(x-3)}{\sqrt{(x-2).(x-3)}}dx$$=\int\limits\frac{dx}{\sqrt{x-3}}-\int\limits\frac{dx}{\sqrt{x-2}}$$=2\sqrt{x-3}-2\sqrt{x-2}+C$ $\int\limits\frac{dx}{\sqrt{(x-2).(x-3)}}=\int\limits\frac{(x-2)-(x-3)}{\sqrt{(x-2).(x-3)}}dx$$=\int\limits\frac{dx}{\sqrt{x-3}}-\int\limits\frac{dx}{\sqrt{x-2}}$$=2\sqrt{x-3}-2\sqrt{x+-2}+C$ $\int\limits\frac{dx}{\sqrt{(x-2).(x-3)}}=\int\limits\frac{(x-2)-(x-3)}{\sqrt{(x-2).(x-3)}}dx$$=\int\limits\frac{dx}{\sqrt{x-3}}-\int\limits\frac{dx}{\sqrt{x-2}}$$=2\sqrt{x-3}-2\sqrt{x-2}+C$

	3	sửa đáp án		Sửa 01-01-14 10:17 AM m_internet001 154 5
$\int\limits\frac{dx}{\sqrt{(x-2).(x-3)}}=\int\limits\frac{(x-2)-(x-3)}{\sqrt{(x-2).(x-3)}}dx$$=\int\limits\frac{dx}{\sqrt{x-3}}-\int\limits\frac{dx}{\sqrt{x-2}}$$=2\sqrt{x-3}-2\sqrt{x+-2}+C$ $\int\limits\frac{dx}{\sqrt{(x-2).(x-3)}}=\int\limits\frac{(x-2)-(x-3)}{\sqrt{(x-2).(x-3)}}dx$$=\int\limits\frac{dx}{\sqrt{x-3}}+\int\limits\frac{dx}{\sqrt{x-2}}$$=2\sqrt{x-3}-2\sqrt{x+-2}+C$ $\int\limits\frac{dx}{\sqrt{(x-2).(x-3)}}=\int\limits\frac{(x-2)-(x-3)}{\sqrt{(x-2).(x-3)}}dx$$=\int\limits\frac{dx}{\sqrt{x-3}}-\int\limits\frac{dx}{\sqrt{x-2}}$$=2\sqrt{x-3}-2\sqrt{x+-2}+C$

	2	thêm 35 ký tự trong đáp án		Sửa 01-01-14 10:16 AM m_internet001 154 5
$\int\limits\frac{dx}{\sqrt{(x-2).(x-3)}}=\int\limits\frac{(x-2)-(x-3)}{\sqrt{(x-2).(x-3)}}dx$$=\int\limits\frac{dx}{\sqrt{x-3}}+\int\limits\frac{dx}{\sqrt{x-2}}$$=2\sqrt{x-3}-2\sqrt{x+-2}+C$ $\int\limits\frac{dx}{\sqrt{x^x-5x+(\frac{5}{2})^2-\frac{1}{4}}}=\int\limits\frac{dx}{\sqrt{(x-\frac{5}{2})^2-(\frac{1}{2})^2}}$Tới đây chắc giải dc rồi chứ $\int\limits\frac{dx}{\sqrt{(x-2).(x-3)}}=\int\limits\frac{(x-2)-(x-3)}{\sqrt{(x-2).(x-3)}}dx$$=\int\limits\frac{dx}{\sqrt{x-3}}+\int\limits\frac{dx}{\sqrt{x-2}}$$=2\sqrt{x-3}-2\sqrt{x+-2}+C$

	1	tạo mới		Trả lời 01-01-14 10:10 AM m_internet001 154 5
$\int\limits\frac{dx}{\sqrt{x^x-5x+(\frac{5}{2})^2-\frac{1}{4}}}=\int\limits\frac{dx}{\sqrt{(x-\frac{5}{2})^2-(\frac{1}{2})^2}}$Tới đây chắc giải dc rồi chứ