$=\mathop {\lim }\limits_{x \to +\infty } \sqrt[3] {\frac{2+\frac{1}{x^2}-\frac{1}{x^5}}{(2-\frac{1}{x^2})(1+\frac{1}{x^2})}}$$= \sqrt[3]{\frac{2+0+0}{(2-0)(1+0)}}=1$
$=\mathop {\lim }\limits_{x \to +\infty } \sqrt[3] {\frac{2+\frac{1}{x^2}-\frac{1}{x^5}}{(2-\frac{1}{x^2})(1+\frac{1}{x^2})}}$$= \frac{2+0+0}{(2-0)(1+0)}=1$
$=\mathop {\lim }\limits_{x \to +\infty } \sqrt[3] {\frac{2+\frac{1}{x^2}-\frac{1}{x^5}}{(2-\frac{1}{x^2})(1+\frac{1}{x^2})}}$$= \
sqrt[3]{\frac{2+0+0}{(2-0)(1+0)
}}=1$