$A=\frac{(x^2+10x+16)(x^2+10x+24)+2008}{x^2+10x+21}$đặt$: x^2+10x+16=a\Rightarrow A=\frac{a^2+8a+2008}{a+5}=\frac{(a+5)(a+3)+1993}{a+5}$vậy dư là $1993$
$A=\frac{(x^2+10x+16)(x^2+10x+24)+2008}{x^2+10x+21}$đặt$: x^2+10x+16=a\Rightarrow A=\frac{a^2+8a+2008}{a+5}=\frac{(a+5)(a+3)+1993}{t+5}$vậy dư là $1993$
$A=\frac{(x^2+10x+16)(x^2+10x+24)+2008}{x^2+10x+21}$đặt$: x^2+10x+16=a\Rightarrow A=\frac{a^2+8a+2008}{a+5}=\frac{(a+5)(a+3)+1993}{
a+5}$vậy dư là $1993$