Thay $2015=a+b+c$ vào$VT=\sum_{cyc}^{}\frac{b+c}{a}+2\geq 2\sqrt{2} \sum_{cyc}^{}\sqrt{\frac{b+c}{a}}=2\sqrt{2}\sum_{cyc}^{}\sqrt{\frac{2015-a}{a}} $ (AM-GM)
Thay $2015=a+b+c$ vào$VT=\sum_{cyc}^{}
(\frac{b+c}{a}+2
)\geq 2\sqrt{2} \sum_{cyc}^{}\sqrt{\frac{b+c}{a}}=2\sqrt{2}\sum_{cyc}^{}\sqrt{\frac{2015-a}{a}} $ (AM-GM)