$\omega=\sqrt{\frac{g}{\Delta l_0}}$ $\Delta l_0=A$ do gian lo xo khi treo m$\Rightarrow\Delta l_0=\frac{g}{\omega ^{{2}}}$ ta co $A^{2}=\frac{v^{2}}{\omega^{2}}+\frac{a^{2}}{\omega^{4}}$$\Leftrightarrow \omega=5\sqrt{3} rad/s$
$\omega=\sqrt{\frac{g}{\Delta l_0}}$ $\Delta l_0=A$
độ gi
ãn l
ò xo khi treo
vật m$\Rightarrow\Delta l_0
=A=\frac{g}{\omega ^{{2}}}$ ta c
ó $A^{2}=\frac{v^{2}}{\omega^{2}}+\frac{a^{2}}{\omega^{4}}$$\Leftrightarrow \omega=5\sqrt{3} rad/s$