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ta co: i1=0,8 mm; i2 =0,96 mm.xet ;$\frac{L}{i1}=25\Rightarrow $ buc xa nay tao ra 25 van sangxet :$\frac{L}{i2}=20,8\Rightarrow $ buc xa nay tao ra 21 van sang$\Rightarrow $co so van sang do 2 buc xa la :N=25+21=46

ta co: i1=0,8 mm; i2 =0,96 mm.xet ;$\frac{L}{i1}=25\Rightarrow $ buc xa nay tao ra 25 van sangxet :$\frac{L}{i2}=20,8\Rightarrow $ buc xa nay tao ra 21 van sang$\Rightarrow $co so van sang la :N=25+21=46

ta co: i1=0,8 mm; i2 =0,96 mm.xet ;$\frac{L}{i1}=25\Rightarrow $ buc xa nay tao ra 25 van sangxet :$\frac{L}{i2}=20,8\Rightarrow $ buc xa nay tao ra 21 van sangso vi tri trung nhau cua 2 van sang thoa man :k1.i1=k2.i2 $\Rightarrow \frac{k1}{k2}=\frac{\lambda2}{\lambda1}=\pm \frac{6}{5}=\pm \frac{12}{10}=\pm \frac{18}{15}=\pm \frac{24}{20}$$\Rightarrow $co so van sang la :N=25+21=41

ta co: i1=0,8 mm; i2 =0,96 mm.xet ;$\frac{L}{i1}=25\Rightarrow $ buc xa nay tao ra 25 van sangxet :$\frac{L}{i2}=20,8\Rightarrow $ buc xa nay tao ra 21 van sangso vi tri trung nhau cua 2 van sang thoa man :k1.i1=k2.i2 $\Rightarrow \frac{k1}{k2}=\frac{\lambda2}{\lambda1}=\pm \frac{6}{5}=\pm \frac{12}{10}=\pm \frac{18}{15}=\pm \frac{24}{20}$$\Rightarrow $cso van sang la :N=25+21=41

ta co: i1=0,8 mm; i2 =0,96 mm.xet ;$\frac{L}{i1}=25\Rightarrow $ buc xa nay tao ra 25 van sangxet :$\frac{L}{i2}=20,8\Rightarrow $ buc xa nay tao ra 21 van sangso vi tri trung nhau cua 2 van sang thoa man :k1.i1=k2.i2 $\Rightarrow \frac{k1}{k2}=\frac{\lambda2}{\lambda1}=\pm \frac{6}{5}=\pm \frac{12}{10}=\pm \frac{18}{15}=\pm \frac{24}{20}$$\Rightarrow $tren toan vung giao thoa , co 9 van sang (ke ca van trung tam)$\Rightarrow $cso van sang la :N=(25+21)-9=37