Ta có $KC max=\sqrt{A_1^2+A_2^2-2A_1A_2.cos(\Delta\varphi)}==>\Delta \varphi=\frac{\pi}3$$W_đ2=\frac{W}4$
Ta có $KC max=\sqrt{A_1^2+A_2^2-2A_1A_2.cos(\Delta\varphi)}==>\Delta \varphi=\frac{2\pi}3$$W_đ2=\frac{W}4$
Ta có $KC max=\sqrt{A_1^2+A_2^2-2A_1A_2.cos(\Delta\varphi)}==>\Delta \varphi=\frac{\pi}3$$W_đ2=\frac{W}4$