Theo đề bài ta có:E_{A} = k\tfrac{q}{OA^{2}} =64E_{B} = k\tfrac{q}{OB^{2}} =9E_{M} = k\tfrac{q}{OM^{2}} \frac{OA}{OB} = \frac{3}{8}--> \frac{8}{3}OA=OB ; OM= \frac{OA+OB}{2} = \frac{11OA}{6}\frac{E_{M}}{E_{A}} = \frac{OA^{2}}{OM^{2}} = \frac{36}{121} ; E_{A} = 64 ---> E_{M} = 19 (V/m)
Theo đề bài ta có:
$E_{A}
$=
$\frac{
kq}{OA^{2}}
$=64
$E_{B}
$=
$\frac{
kq}{OB^{2}}
$ =9
$E_{M}
$=
$\frac{
kq}{OM^{2}}
$$\frac{OA}{OB}
$=
$\frac{3}{8}
$-->
$\frac{8}{3}
$OA=OB ; OM=
$\frac{OA+OB}{2}
$=
$\frac{11OA}{6}
$ $\frac{E_{M}}{E_{A}}
$ =
$\frac{OA^{2}}{OM^{2}}
$ =
$\frac{36}{121}
$$E_{A}
$= 64 --->
$E_{M}
$= 19 (V/m)