$\frac{T}{6}=\frac{1}{360}s$Vì $q'(t)=i(t)$ nên $\Delta q = \int\limits_{0}^{\frac{1}{360}} \sqrt{2}\ \cos(120\pi t - \frac{\pi}{3})dt =3,25.10^{-3}\ (C)$Đáp án: $A$----------------------Edit: sửa cận thời gian
$\frac{T}{6}=\frac{1}{360}s$Vì $q'(t)=i(t)$ nên $\Delta q = \int\limits_{a}^{b} \sqrt{2}\ \cos(120\pi t - \frac{\pi}{3})dt =3,25.10^{-3}\ (C)$Đáp án: $A$
$\frac{T}{6}=\frac{1}{360}s$Vì $q'(t)=i(t)$ nên $\Delta q = \int\limits_{
0}^{
\frac{1}{360}} \sqrt{2}\ \cos(120\pi t - \frac{\pi}{3})dt =3,25.10^{-3}\ (C)$Đáp án: $A$
----------------------Edit: sửa cận thời gian