1,ĐK −3≤x≤1Bình phương 2 vế⇒4−2√3−2x−x2=x2+2x+1⇒−2√3−2x−x2=x2+2x−3Bình phương 2 về⇒4(3−2x−x2)=x4+4x3−2x2−12x+9⇒x4+4x3+2x2−4x−3=0⇒(x−1)(x+1)2(x+3)=0⇒x=±1;−32,
1,ĐK −3≤x≤1Bình phương 2 vế⇒4−2√3−2x−x2=x2+2x+1⇒−2√3−2x−x2=x2+2x−3Bình phương 2 về⇒4(3−2x−x2)=x4+4x3−2x2−12x+9⇒x4+4x3+2x2−4x−3=0⇒(x−1)(x+1)2(x+3)=0⇒x=±1;−3