Theo đề bài ta có:E_{A} = k\tfrac{q}{OA^{2}} =64E_{B} = k\tfrac{q}{OB^{2}} =9E_{M} = k\tfrac{q}{OM^{2}} \frac{OA}{OB} = \frac{3}{8}--> \frac{8}{3}OA=OB ; OM= \frac{OA+OB}{2} = \frac{11OA}{6}\frac{E_{M}}{E_{A}} = \frac{OA^{2}}{OM^{2}} = \frac{36}{121} ; E_{A} = 64 ---> E_{M} = 19 (V/m)
Theo đề bài ta có:$E_{A} $=$\frac{kq}{OA^{2}} $=64$E_{B} $= $\frac{kq}{OB^{2}} $ =9$E_{M} $= $\frac{kq}{OM^{2}} $$\frac{OA}{OB} $= $\frac{3}{8} $--> $\frac{8}{3} $OA=OB ; OM=$\frac{OA+OB}{2} $= $\frac{11OA}{6} $ $\frac{E_{M}}{E_{A}} $ = $\frac{OA^{2}}{OM^{2}} $ = $\frac{36}{121} $$E_{A} $= 64 ---> $E_{M} $= 19 (V/m)