1: ĐK $x>\dfrac{2}{3}$
BPT $\Leftrightarrow (x^2-3x+2)>(1-x)\sqrt{3x-2}$
$\Leftrightarrow (x-1)(x-2) +(x-1)\sqrt{3x-2}>0$
$(x-1) [ x-2 +\sqrt{3x-2} ] >0 \ (*)$
TH1: $x>1 \Rightarrow \sqrt{3x-2} -2+x >0 \ (*)$ đúng
TH2: $\dfrac{2}{3} <x <1 \Rightarrow \sqrt{3x-2} -2+x<0 \ (*)$ đúng
KL: $\left [ \begin{matrix} x>1 \\ \dfrac{2}{3} <x <1 \end{matrix} \right.$