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PT(1): 2xy−x+4y=(2y+1)√x2+2y
⇔(2y+1)(−√x2+2y+x+1)+2y−2x−1=0
⇔(2x−2y+1)(2y+1x+1+√x2+2y−1)=0
⇔(2x−2y+1)(2y−x−√x2+2y)=0
⇔(2x−2y+1).2y(2y−2x−1)2y−x+√x2+2y=0
⇔2x−2y+1=0 (do ĐKXĐ nên y>0)
Thay PT(2):
3x−2=√4x−1+√3x2+2x−1≥0
⇔(x−1−√4x−1)+(2x−1−√3x2+2x−1)=0
⇔(x2−6x+2).3x−2+√4x−1+√3x2+2x−1(x−1−√4x−1)(2x−1−√3x2+2x−1)=0
⇔x2−6x+2=0
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