Đăng bài 04-05-12 03:07 PM
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Giải phương trình : ${8.3^{\sqrt x + \sqrt[4]{x}}} + {9.^{\sqrt[4]{x} + 1}} = {9^{\sqrt x }}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\left( 1 \right)$
Đăng bài 04-05-12 12:02 PM
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Giải các phương trình:
$\begin{array}{l}
1)\,{3.2^{\frac{{x - 1}}{{x + 1}}}} - {8.2^{\frac{{\sqrt x - 1}}{2} }
+ 4 } =
0\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(1)\\
2)\,\,{81^x} - {16^x} - 2\left( {{9^x} - {4^x}} \right) + {36^x} =
0\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(2)
\end{array}$
Đăng bài 04-05-12 11:49 AM
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Đăng bài 04-05-12 11:47 AM
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Đăng bài 04-05-12 11:45 AM
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Giải phương trình :
${2^{{x^2} + 4}} = {2^{2\left( {{x^2} + 1} \right)}} + \sqrt {{2^{2\left( {{x^2} + 2} \right)}} -
{2^{{x^2} + 3}} + 1} \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(1)$
Đăng bài 04-05-12 11:44 AM
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Giải các phương trình :
$\begin{array}{l}
1)\,\,{x^{3 - \log \frac{x}{3}}} =
900\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,
\,\,\,3)\,\,{8^{{x^3} - 1}} + {18^{{x^3} - 1}} = {2.27^{{x^3} - 1}}\\
2)\,\,{49^{\frac{1}{x}}} - {35^{\frac{1}{x}}} =
{25^{\frac{1}{x}}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,4)\,\,{4.3^x} - {9.2^x} = {5.6^{\frac{x}{2}}}
\end{array}$
Đăng bài 04-05-12 11:43 AM
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Giải các phương trình :
$\begin{array}{l}
1)\,{\left[ {{{\left( {{2^{\sqrt x + 5}}} \right)}^{\frac{1}{{5\sqrt x + 1}}}}}
\right]^{\frac{1}{{\sqrt x }}}} = \frac{1}{2}{.4^{\sqrt x
}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,
\,\,\,\,\,\,\,\,\,\,(1)\\
2)\,\,{2^{{{\log }_8}\left( {{x^2} - 6x + 9} \right)}} = {3^{2{{\log }_x}\sqrt x -
1}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\
,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(2)\end{array}$
Đăng bài 04-05-12 11:07 AM
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Giải các phương trình:
$\begin{array}{l}
1)\,\,{3^{2 + x}} + {3^{2 - x}} =
30\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,3)\,\,{25^x} - {23.5^x} - 5 = 0\\
2)\,{4^x} + {3.2^x} - 10 = 0\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,4)\,\,{3^{2\left( {x
+ 1} \right)}} - {82.3^x} + 9 = 0
\end{array}$
Đăng bài 04-05-12 11:04 AM
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Đăng bài 04-05-12 10:20 AM
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Đăng bài 04-05-12 10:13 AM
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Đăng bài 02-05-12 02:12 PM
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Đăng bài 02-05-12 11:53 AM
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Đăng bài 02-05-12 11:11 AM
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Đăng bài 27-04-12 02:38 PM
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Đăng bài 27-04-12 02:35 PM
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Đăng bài 27-04-12 10:37 AM
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Đăng bài 27-04-12 10:24 AM
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Đăng bài 27-04-12 08:28 AM
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Đăng bài 27-04-12 08:26 AM
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Đăng bài 27-04-12 08:17 AM
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Giải phương trình :
$2co{s^2}\frac{{{x^2} + x}}{6} = {2^x} + {2^{ - x}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(1)$
Đăng bài 26-04-12 03:34 PM
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Giải phương trình :
$x{.2^x} = x\left( {3 - x} \right) + 2\left( {{2^x} - 1} \right)\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(1)$
Đăng bài 26-04-12 03:25 PM
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Giải phương trình :
$8 - x{.2^x} + {2^{3 - x}} - x = 0\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(1)$
Đăng bài 26-04-12 03:23 PM
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Đăng bài 26-04-12 03:20 PM
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Giải phương trình :
${2^{x + 1}} - {4^x} = x - 1\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(1)$
Đăng bài 26-04-12 03:20 PM
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Mỗi phương trình sau đây có bao nhiêu nghiệm :
$\begin{array}{l}
1)\,\,{\left( {\frac{1}{3}} \right)^x} = 2x + 1\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(1)\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,3)\,{4^x} = x - 2\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(3)\\
2)\,{3^x} = x + 5\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(2)
\end{array}$
Đăng bài 26-04-12 03:16 PM
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Đăng bài 26-04-12 03:14 PM
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Giải các phương trình sau đây :
$\begin{array}{l}
1)\,\,{3^x} + {4^x} = {5^x}\,\,\,\,\,\,\,\,(1)\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,4)\,\,\,{3^x} + {4^x} + {5^x}\, = {10^x}\,\,\,\,\,\,\,\,\,\,\,\,(4)\\
2)\,{2^x} + {3^x} = {5^x}\,\,\,\,\,\,\,\,(2)\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,5)\,\,\,\log \left( {x - 4} \right) = 5 - x\,\,\,\,\,\,\,\,\,\,\,\,\,\,(5)\\
3)\,{5^x} + {12^x} = {13^x}\,\,\,\,(3)
\end{array}$
Đăng bài 26-04-12 03:03 PM
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Đăng bài 26-04-12 09:22 AM
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