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Phương trình tương đương với:
$\sin17x=\frac{\sqrt3}{2}\cos 5x-\frac{1}{2}\sin5x$
$\Leftrightarrow \sin17x=\sin(\frac{\pi}{3}-5x)$
$\Leftrightarrow \left[ \begin{array}{l} 17x=\frac{\pi}{3}-5x+k2\pi\\ 17x=\frac{2\pi}{3}+5x+k2\pi \end{array} \right.,k\in\mathbb{Z}$
$\Leftrightarrow \left[ \begin{array}{l} x=\frac{\pi}{66}+\frac{k}{11}\pi\\ x=\frac{\pi}{18}+\frac{k}{6}\pi \end{array} \right. ,k\in\mathbb{Z} $
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