tacósinA+sinB+sinCcosA+cosB+cosC=√3⇔sinA+sinB+sinC=√3(cosA+cosB+cosC)
⇔sinA−√3cosA+sinB−√3cosB+sinC−√3cosC=0
⇔sinA−√3cosA2+sinB−√3cosB2+sinC−√3cosC2=0
⇔sin(A−π3)+sin(B−π3)+sin(C−π3)=0
⇔2sin(A+B−2π32).cosA−B2+sin[π−(A+B)−π3]
⇔2sin(..........nt..............)+cos[π3−(A+B2)]=0
⇔2sinA+B−2π32=0(1) hoặc cosA+B2=cos(π3−A+B2)(2)
(1) ⇒ˆC=60
(2)⇒ˆA=ˆB=60
⇒ΔABC có ít nhất 1 góc = 60